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The else block when catching exceptions in Python

You can also add a else block to the try-except construct. An important nuance is that the code placed in the else block will work if no exceptions were caught before it in try-except.

Let's say we have a list:

lst = [1, 2, 3]

In the try-except construction, we will write an exception catch for a non-existent list element:

try: print(lst[4]) except IndexError: print('error: elem is not exist')

Now let's specify in the else block the output of the sum of all elements of the list:

try: print(lst[4]) except IndexError: print('error: elem is not exist') else: print(sum(lst))

If the code in the try block refers to a missing element, an error message will appear in the console:

'error: elem is not exist'

Now let's set the try block to output an element that is definitely in the list:

try: print(lst[0]) except IndexError: print('error: elem is not exist') else: print(sum(lst))

After executing the code, two numbers will appear in the console: the element specified in try and the sum of all elements of the list:

1 6

Given a list:

lst = [1, 2, 3]

Write code to catch the division by zero exception. If the exception does not occur, print the length of the list.

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