Safe Extraction Operator in OOP in PHP

The safe extraction operator ?-> allows safely accessing methods and properties of objects that can be null.

Let's look at an example. Suppose we have the following class:

<?php
	class User
	{
		public $name;
		
		public function __construct($name)
		{
			$this->name = $name;
		}
	}
?>

Let's create an object of this class:

<?php
	$user = new User('john');
?>

Let's output the value of its property:

<?php
	$user = new User('john');
	echo $user->name;
?>

Suppose now it happened that instead of an object we have null. In this case, an attempt to access the user's name will lead to an error:

<?php
	$user = null;
	echo $user->name; // error
?>

To suppress the error, we can use the safe extraction operator:

<?php
	$user = null;
	echo $user?->name;
?>

Improve the following code using the safe extraction operator:

<?php
	class Employee {
		public $name;
		public $salary;
		
		public function __construct($name, $salary)
		{
			$this->name = $name;
			$this->salary = $salary;
		}
	}
	
	$employee = new Employee('john', 1000);
	
	echo $employee->name;
	echo $employee->salary;
?>