Rethrowing an exception in JavaScript

Let's consider the catch-block of the task with product JSON:

catch (error) {
	if (error.name == 'SyntaxError') {
		alert('Invalid JSON of the product');
	} else if (error.name == 'ProductCostError') {
		alert('Product has no price or amount');
	}
}

As you can see, we catch the two exceptions we planned and somehow react to it. But what happens if an exception of a different type that we didn't expect occurs? In this case, it will also fall into a catch-block, but there will be no reaction to this, since the exception with a different type simply will not fall into any of our IFs.

When I say that there will be no reaction, I mean that there really is none: there will not even be an error thrown into the console. Our code just silently won't work.

Therefore, there is the following rule: your code should only catch exceptions that it knows how to handle. If the exception is not known, then it must be rethrow further with throw. In this case, someone more knowledgeable will catch it above, or an exception will be thrown into the console as an error.

Let's fix our code:

catch (error) {
	if (error.name == 'SyntaxError') {
		alert('Invalid JSON of the product');
	} else if (error.name == 'ProductCostError') {
		alert('Product has no price or amount');
	} else {
		throw error; // rethrow the exception further
	}
}

Given the following code:

try {
	let arr = JSON.parse(json);

	for (let i = 0; i < arr.length; i++) {
		localStorage.setItem(i, arr[i]);
	}
} catch (error) {
	if (error.name == 'QuotaExceededError') {
		alert('ran out of storage space');
	}
	
	if (error.name == 'SyntaxError') {
		alert('invalid json');
	}
}

What's wrong with this code? Fix it for a better one.