Нужна помощь донатом
для написания учебников Kotlin, Java, C++, C#, Go, Rust, Dart
подробности по ссылке
⊗jsPmCdExHP 136 of 504 menu
◀ ▶

Checking parts of hour with if-else in JavaScript

Suppose we have the variable min that stores the number of minutes from 1 to 60:

let min = 10;

Let's determine in which quarter of an hour the specified number of minutes falls:

let min = 10; if (min >= 0 && min <= 14) { console.log('1st quarter'); } if (min >= 15 && min <= 29) { console.log('2nd quarter'); } if (min >= 30 && min <= 44) { console.log('3rd quarter'); } if (min >= 45 && min <= 59) { console.log('4th quarter'); }

Solve a similar problem, only determine what third of the hour the specified number of minutes falls in.

← →
↑
English▼
AfrikaansAzərbaycanБългарскиবাংলাБеларускаяČeštinaDanskDeutschΕλληνικάEspañolEestiSuomiFrançaisहिन्दीMagyarՀայերենIndonesiaItaliano日本語ქართულიҚазақ한국어КыргызчаLietuviųLatviešuМакедонскиMelayuမြန်မာNederlandsNorskPolskiPortuguêsRomânăРусскийසිංහලSlovenčinaSlovenščinaShqipСрпскиSrpskiSvenskaKiswahiliТоҷикӣไทยTürkmenTürkçeЎзбекOʻzbekTiếng Việt
We use cookies for website operation, analytics, and personalization. Data processing is carried out in accordance with the Privacy Policy.
accept all customize decline