Uwongo wa Mara Moja wa Viterushaji katika JavaScript

Kila kiterushaji kiweze kushiriki katika kitanzi mara moja tu. Hii inashangaza kidogo, lakini ina mantiki - baada ya yote, kiterushaji kilichopita hukiweka done yake kuwa false, na kwa hivyo hakiwezi tena kusomwa.

Hebu tuhakikishe hili. Tuchukulie tuna kizalisaji kifuatacho:

function *func() {
	yield 1;
	yield 2;
	yield 3;
}

Tutengeneze kiterushaji:

let iter = func();

Wacha tusome kiterushaji kwa kitanzi kimoja:

for (let elem of iter) {
	console.log(elem); // 1, 2, 3
}

Sasa tusome kiterushaji kwa vitanzi viwili:

for (let elem of iter) {
	console.log(elem); // 1, 2, 3
}
for (let elem of iter) {
	console.log(elem); // haifanyi kazi
}

Ili kutatua tatizo inahitajika kwa kila kitanzi kipya kuunda kiterushaji chake:

let iter1 = func();
for (let elem of iter1) {
	console.log(elem); // 1, 2, 3
}

let iter2 = func();
for (let elem of iter2) {
	console.log(elem); // 1, 2, 3
}

Tunaweza kurahisisha:

for (let elem of func()) {
	console.log(elem); // 1, 2, 3
}

for (let elem of func()) {
	console.log(elem); // 1, 2, 3
}

Sahihisha makosa yaliyofanyika katika msimbo ufuatao:

function *func() {
	for (let i = 1; i <= 3; i++) {
		yield i;
	}
}

let elems = func();

for (let elem of elems) {
	console.log(elem);
}
for (let elem of elems) {
	console.log(elem);
}